A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with the velocity of 80m/s. The height of the tower is (g-10m/s²)....
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The initial velocity of the ball is =20 m/s.
The final velocity of the ball is =80 m/s.
The acceleration due to gravity is =10 m/s²
So, the height of the tower can be obtained from the expression:v²=u²+2gh
Substitute the values in above expression:
80²=20²+(2×10×h)
h=6400-400/20m
h=6000/20->300m.
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