Question

a ball is thrown vertically up and returns to thrower after 6sec find -
a) The velocity with which it was thrown up
b) the maximum distance up to which it was raised (g= 10m/s^2

Answer 1

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Answer 2

hey
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a.

t = 3 seconds
v = 0
g= -10m / s square ( as its thrown against the motion )
u= ?

using first equation of motion
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v= u + gt
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0 = u -10*3
30 m / s = u

b.

h = ?
g= -10m / s square
t= 3 seconds
v= 0

using third equation of motion
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v square - u square = 2gh
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(0)whole square - (30) whole square = -20h
-900 = -20h
900 / 20 =h
45 m = h

hence , h = 45m

• note - as we know that in the case of free falling body the body takes equal interval of time while going up and in coming downward

• so here total time is given 6 seconds
it means it took 3 seconds while going upward
and 3 seconds while going downward

hope helped
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