a ball is thrown vertically upward from the ground with a speed of 24.5m/s. After what time intervals,the ball will be at a height of 29.4m from the ground?
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Answer:
Explanation:
=> Here, a ball is thrown vertically upward from the ground with a speed of 24.5m/s, and reach the height of 29.4 m
=>According to the formula of height,
h = vt - 1/2gt²
where,
h = height = 29.4 m
v = speed = 24.5 m/s.
g = acceleration of gravity = 9.8 m/s²
=> h = vt - 1/2gt²
∴ 29.4 = 24.5t - 1/2 (9.8)t²
58.8 = 49t - 9.8t²
6 = 5t - t²
t² - 5t + 6 = 0
t² - 2t - 3t + 6 = 0
t (t - 2) - 3(t - 2) = 0
(t - 2) (t - 3) = 0
t = 2 or 3
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