a ball is thrown vertically upward from the ground with the velocity of 30m/s. find the distance of ball from the ground after 2sec of throwing. (g=10m/s^2)
Answers
Explanation:
thrown vertically upward from the ground with the velocity of 30m/s. find the distance of ball from the ground after 2sec of throwing. (g=10m/s^2)
Distance of ball from the ground after 2 sec of throwing is 40 m if thrown with velocity of 30 m/s
Given : A ball is thrown vertically upward from the ground with the velocity of 30m/s.
To find : the distance of ball from the ground after 2 sec of throwing. (g=10m/s²)
Solution:
S = ut + (1/2)at²
u = 30 m/s
a = -g = -10 m/s²
t = 2 secs
S = 30 *2 + (1/2)(-10)(2)²
= 60 - 20
= 40 m
distance of ball from the ground after 2 sec of throwing = 40 m
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