A ball is thrown vertically upward with a speed of 21.0 m/s.
(a) How high does it rise?
m
(b) How long does it take to reach its highest point?
s
(c) How long does the ball take to hit the ground after it reaches its highest point?
s
(d) What is its velocity when it returns to the level from which it started?
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Answer:
a). 22m
b). 2.1 sec
c). 20.9 m/sec
d). 2.01 sec
Explanation:
a). v²= u²+ 2as
as it reach to higest point its velocity became zero so, v=o
o=21×21+2(10)(s)
s=22m
b). v=u+at
0=21+(10)(t). ( v=o)
t=2.01 sec
c). v²= u²+2as
v²=o+2(10)(22)
v= 20.9
d). v=u+at
20.9=10(t)
t=2.09
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