if unicorn a is 49x older than unicorn b, and their ages sum up 1450, how old is each unicorn
Answers
Answered by
2
Answer: let the age of unicorn a be 49x and age of unicorn b be x
According to the question
49x + x = 1450
50x = 1450
x = 1450/50
x = 29
age of unicorn a = 49*29= 1421 years
age of unicorn b = 29 years
Answered by
2
Correct Question :- if unicorn a is 49 times than unicorn b, and their ages sum up 1450, how old is each unicorn ?
Solution :-
Let us assume that, age of unicorn b is equal to x years .
So,
→ Age of unicorn b = 49 * x = 49x years .
then,
→ x + 49x = 1450
→ 50x = 1450
→ x = 29 years .
therefore,
→ Age of unicorn b = x = 29 years .
→ Age of unicorn a = 49x = 49 * 29 = 1421 years .
Learn more :-
write the equivalent fraction with denominator 100 of 7/10
https://brainly.in/question/22299752
Similar questions