Question

A ball is thrown vertically upward with a velocity of 10 m/s. Calculate the height attained by the ball and time taken by it to reach the highest point if the acceleration of the ball is -10 m/s2during its motion.

Answer 1

Given:

Initial velocity = 10m/s

Final velocity = 0

acceleration due to gravity , g = -10m/s

(when a body is thrown vertically upwards,its velocity goes on decreasing. That's why the value of g is taken negative. )

To Find:

• Height
• time

Solution:

By using first equation of motion -

V=u+gt

we, can derive -

t = v-u/g

t = 0-10/- 10

t = 1 second

$\boxed{\boxed{\boxed{\mathfrak{time = 1 second}}}}$

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Now, using second equation of motion-

s= ut+1/2at^2

s = 10×1+1/2×(-10)×(1)^2

s = 10 + (-5)× 1

s = 10 - 5

s = 5 metres

$\boxed{\boxed{\boxed{\mathfrak{s = 5 metres}}}}$

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