Question

A ball is thrown vertically upwards from the top of a tower at 4.9 metre per second it strike the pond near the base of camera after 3 seconds the height of the tower is

Answer 1

Answer:

29.4

Explanation:

Given A ball is thrown vertically upwards from the top of a tower at 4.9 metre per second it strike the pond near the base of camera after 3 seconds the height of the tower is

We know that from equation of motion

S = ut + ½ gt^2

Since ball is thrown vertically upward u is negative.

So S = - 4.9 x 3 + 1/2 x 9.8 x 9

    S = - 14.7 + 44.1

    S = 29.4 m

So the height of the tower is 29.4 m