A ball is thrown vertically upwards from the top of a
tower with an initial velocity of 19.6 m s-1. The ball
reaches the ground after 5 s. Calculate : (i) the height
of the tower, (ii) the velocity of ball on reaching the
ground. Take 8 = 9.8 m s-2
24.5 m (i) 29.4 m s-1
Answers
Answered by
2
Answer:
1. height = 9.8 + 24.5 = Ans .
2.this will be 5s + 19.6 = Ans .
Step-by-step explanation:
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Answered by
2
Answer:
guys by process or not but I am answering u 53.5
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