Physics, asked by Balaji167, 1 year ago

A ball is thrown vertically upwards with a velocity of 30 M per second calculate the time taken to reach maximum height

Answers

Answered by Anonymous
0

Many of the answers here provide an equation, and simply suggest to input values and isolate for the variable. However, there is a much simpler manner to examine this question.

If a ball is thrown vertically in the air, with a velocity of 30 m/s, there is only one significant force which is acting against the ball (assuming air resistance is negligible). That force would be gravity. The acceleration due to gravity is known to be #10m/sec^2#

(I took the value as 10, rather than 9.8, 9.81, or any other more specific value because it simplifies the explanation, and more significant digits are not necessarily required given the value for velocity is only one significant digit.)

What this essentially means is that the velocity of the ball in the vertical axis decreases by 10m/s, for every second that it is in motion.

In order to find the time the ball reaches the maximum height, you must find when the velocity of the ball in the vertical axis reaches 0. We could simply take the initial velocity, and dividing by the value of acceleration due to gravity.

#30m/sec^2/10m/sec^2#

Therefore, the time the ball takes to reach the maximum height is 3 seconds.


jdsajwan: We know equation of motion
gourmahesh196pbalqo: my answer is right / wrong
gourmahesh196pbalqo: mene aapko maximum height bta di sorry
Answered by gourmahesh196pbalqo
0
u=30 a= -g v= 0. then answer is 45 m
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