Find the value of k, if the point P(2,3) is equidistant from the points A(k,1) and B(7,k)
Answers
Answered by
40
AP = BP
root of (2-k)^2+2^2 = root of (-5)^2 + (3-k)^2
squaring both the sides
4+k^2-4k+4=25+9+k^2-6k
-4k+8=34-6k
2k=26
k=13
root of (2-k)^2+2^2 = root of (-5)^2 + (3-k)^2
squaring both the sides
4+k^2-4k+4=25+9+k^2-6k
-4k+8=34-6k
2k=26
k=13
Answered by
58
hope it helps...........
Attachments:
Similar questions