A ball is thrown vertically upwards with speed of 60m/s. distance travelled by particle in time interval t=0 to t=7s is
Answers
Answered by
0
h= ?
u = 60m/s
delta t = 7 s
g= 10m/s^2
h = ut + 1/2 gt^2
h = 60 × 7 + 1/2 × 10 × (7)^2
h = 420 + 5 × 49
h = 420 + 245
h = 665m
So ball will go up to 665m height.
Thanks
u = 60m/s
delta t = 7 s
g= 10m/s^2
h = ut + 1/2 gt^2
h = 60 × 7 + 1/2 × 10 × (7)^2
h = 420 + 5 × 49
h = 420 + 245
h = 665m
So ball will go up to 665m height.
Thanks
Similar questions