A ball mass m falls vertically to the ground from a height h₁
and rebounds to a height h₂. The change in momentum of
the ball of striking the ground is
(a) m √2g(h₁ + h₂ ) (b) n √2g(m₁ +m₂ )
(c) mg(h₁ - h₂ ) (d) m( √2gh₁ - √2gh₂ )
Answers
Answered by
3
Answer:
(a) m √2g(h₁ + h₂ ) (b) n √2g(m₁ +m₂ )
(c) mg(h₁ - h₂ ) (d) m( √2gh₁ - √2gh₂ )
Explanation:
option a is your question mate
Similar questions