Physics, asked by ayushkumar17861, 8 months ago

An open topped rail road car of mass M has an initial velocity
v₀ along a straight horizontal frictionless track. It suddenly
starts raising at time t = 0. The rain drops fall vertically with
velocity u and add a mass m kg/sec of water. The velocity of
car after t second will be (assuming that it is not completely
filled with water)
(a) v₀ + m u/M (b) mv₀/M + mt
(c) MV₀ + ut/M + ut(d) v₀ + mut/M + ut

Answers

Answered by naTEA
1

Answer:

hope you understand mate

Explanation:

(a) v₀ + m u/M (b) mv₀/M + mt

(c) MV₀ + ut/M + ut(d) v₀ + mut/M + ut

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