A ball of lead 4cm in diameter is covered with gold. if the volume of the gold and lead are equal then the thickness of gold
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HEY DEAR.....!!!
r = inner radius of lead sphere = inner radius of gold hollow sphere
R = outer radius of gold sphere
Volume of lead = volume of gold = 4πr³/3
Volume of gold = (4π/3)(R³ - r³)
Since the volumes of lead and gold are equal:
(4π/3)(R³ - r³) = (4π/3)r³
R³ - r³
(4π/3)R³ = (4π/3)(2r³)
R³ = 2r³
Thickness of the gold = R-r
= r(³√2) - r
= r(³√2 - 1)
= 2(³√2 - 1)
≈ 0.51984 cm
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HOPE IT'S HELP U.....☺
r = inner radius of lead sphere = inner radius of gold hollow sphere
R = outer radius of gold sphere
Volume of lead = volume of gold = 4πr³/3
Volume of gold = (4π/3)(R³ - r³)
Since the volumes of lead and gold are equal:
(4π/3)(R³ - r³) = (4π/3)r³
R³ - r³
(4π/3)R³ = (4π/3)(2r³)
R³ = 2r³
Thickness of the gold = R-r
= r(³√2) - r
= r(³√2 - 1)
= 2(³√2 - 1)
≈ 0.51984 cm
@@@@@@@@@@@@@@@@@@@@@@@
HOPE IT'S HELP U.....☺
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