please solve this question
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Given that total number of tickets = 100.
Two tickets are chosen at random = 100C2.
Let A be the event that maximum number on the two chosen tickets is not more than 10.
Let B be the event that the minimum number on the two chosen tickets is 5.
P(A intersection B) = 5C1/100C2 .
P(A) = 10C2/100C2.
Then P(B/A) = P(A intersection B)/P(A)
= 5C1/100C2/(10C2/100C2)
= 5/45
= 1/9.
Hope this helps!
Two tickets are chosen at random = 100C2.
Let A be the event that maximum number on the two chosen tickets is not more than 10.
Let B be the event that the minimum number on the two chosen tickets is 5.
P(A intersection B) = 5C1/100C2 .
P(A) = 10C2/100C2.
Then P(B/A) = P(A intersection B)/P(A)
= 5C1/100C2/(10C2/100C2)
= 5/45
= 1/9.
Hope this helps!
jayu6:
very very thank you
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