Question

A ball of mass 0.25 kg attached to the end of a string of length 1.96 m is moving in a horizontal circle.the string will break if the tension is more than 25 N. what is the maximum speed with which the ball can be moved?

Answer 1

u know
centripetal force=F=mv^2/r
here m=mass of ball=0.25kg
force=F=25N
speed=v=?
r=radius of circle=length of string=1.96m
now put all those values in the equation above
25=0.25*v^2/1.96
tell me v=?

Answer 2

Maximum speed is 14 m/s

Given:

Mass of ball = 0.25 kg  

String length = 1.96 m

Tension = 25 N  

Solution:

The centripetal force causes the horizontal circular motion which is given by the formula given below:

$F=\frac{m v^{2}}{r}$

Here the tension will be the force which cause the maximum speed to attain.

$\therefore F=\frac{m v^{2}}{r}$

$\Rightarrow 25=\frac{0.25 \times v^{2}}{1.96}$

$v^{2}=\frac{25 \times 1.96}{0.25}$

$v^{2}=196 \ m/s$

$v=14 \ m / s$