A ball of mass 1 kg thrown upward reaches a maximum height of 4 m calculate the work done by the force of gravity during the vertical displacement
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Answer:
Work done by the force of gravity during the vertical displacement is -40 Joule.
Explanation:
Given,
m = 1 kg
S = 4 m
W = FS cos theta
W = FS cos 180°
W = FS (-1)
W = - FS
W = - mgS
W = -(1 × 10 × 4) Joule
W = - 40 Joule
Here,
m is the mass of the ball.
S is the vertical displacement.
W is the work done by the force of gravity.
F is the force of gravity.
g is the acceleration due to gravity.
g = 10 m/s^2.
Theta is the angle between force of gravity and vertical displacement i.e., 180°.
Hence,
Work done by the force of gravity during the vertical displacement is -40 Joule.
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