Question

A ball of mass 10g strike the wall and rebounds with same velocity with impulse 0.54 what is velocity

Answer 1

In wall collision, ∆p= -2mvsin(theta)

Since, impulse=∆p

Thus, 0.54= 2* 10* 10^-3 (kgs)* v (theta= 90°)

v= 0.54/2*10^-2

Hence, v= 27 m/s