Question

A ball of mass 10gm is released from a height 500m it renounced from ground in .1 sec find the force applied on ground

Answer 1

v= root(2gh)
v= root(2×10×500)
v= 100m/sec
Pi= -mv= -1 kg m/sec
Pf= 1
F= 2/0.1= 20N