a ball of mass 20 gm is initially moving with a velocity of 100m/s on applying a constant force on the ball for 0.5s , it acquired a velocity of 150m/s . calculate the following:
3. final momentum of the ball.
4. Acceleration of the ball.
5. Magnitude of the force.
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mass of the ball (m) =100g or 0.1kg
initial velocity (u) =25sm
time (t) = 0.025sec.
final velocity (v) = 0
Initial momentum = mu
= 0.1×25
= 2.5 skgm
Final momentum = mv (which is equal to 0, since v is zero)
Change in momentum = mv-mu
= 0 - 2.5 = -2.5 skgm
Average force = timeChangeinmomentum
= - 0.025(2.5)
= -100skgm
= -100 N
The negative sign actually shows that the force was applied
opposite to the direction of the motion of the ball.
So, the average force applied by the player will be 100
Explanation:
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