Question

if the coordinates of two points are P(-6,3) and Q (-8,5),then find (abscissa of P) -(abscissa of Q) ​

Answer 1

(b) We have, points P(- 2, 3) and Q(- 3, 5)

Here, abscissa of Pi.e., x-coordinate of Pis -2 and abscissa of Q i.e., x-coordinate of Q is -3. So, (Abscissa of P) – (Abscissa of Q) = - 2 - (-3) = -2 + 3 =1.

Answer 2

Answer:

2

Step-by-step explanation:

Concept= Coordinate Geometry

Given= Points P and Q

To find= Difference between abscissa

Explanation=

Co ordinate are the Points on the line denoted by (x,y).

Here x is known as abscissa and y as ordinate.

Abscissa is the point on x-axis.

Ordinate is the point on y-axis.

So, in the given points,

P(-6,3)

The abscissa of P is -6

The ordinate of P is 3

Q(-8,5)

The abscissa of Q is -8

The ordinate of Q is 5

We have to now find (abscissa of P) -(abscissa of Q) ​

=> (-6) - (-8)

=> -6 + 8

=> 2

Therefore, the value of (abscissa of P) -(abscissa of Q) ​ is 2.

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