Question

A ball of mass m is dropped on a floor having COR e .find the value of impluse provided by the floor.​

Answer 1

$\huge\star{\tt{\underline{\underline{\red{Answer}}}}}\star$

Speed of ball = V = $\sf\sqrt{2gh}$

$\sf{V_{1}}$ =eV _______✰(1)

By Impulse Momentum Theorem

Impulse (J) = vector P$_{f}$ - vector P$_{i}$

Here p = Momentum

$\implies$ $mV{_{1}} - (-mV)$

$\implies$ $mV{_{1}} + mV$

$\implies$ From (1)

$\implies$$\large{\sf{\boxed{J=mV(1+e)}}}$

Answer 2

$\mathfrak{\huge{\orange{\underline{\underline{Answer :}}}}}$

Speed of ball = V = $\sf\sqrt{2gh}$

$\sf{V_{1}}$ =eV _______✰(1)

By Impulse Momentum Theorem

Impulse (J) = vector P$_{f}$ - vector P$_{i}$

Here p = Momentum

$\implies$ $mV{_{1}} - (-mV)$

$\implies$ $mV{_{1}} + mV$

$\implies$ From (1)

$\implies$$\large{\sf{\boxed{J=mV(1+e)}}}$