Question

A ball rolling down a hill was displaced 19.6 m while uniformly accelerating from rest. If the final velocity was 5.00 m/s. What was the rate of acceleration?

Answer 1

Answer:

0.638m/s2

Explanation:

Use the kinematic relation

vf2 - vi2 = 2ad

vf = final speed = 5.00 m/s

vi = initial speed = 0

d = travel distance = 19.6 m

a = constant acceleration = ?

a = vf2/(2d) = (5.00)2/[2(19.6)] m/s2 ≅ 0.638 m/s2

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