Question

a ball rolling rolling along the ground with velocity of 10 m/s and comes to rest at rest at 8s.Find it's acceleration.
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Answer 1

Answer:

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Answer 2

$\huge\fcolorbox{black}{aqua}{Solution:-}$

✡ Given ✡

A ball rolling along the ground with velocity of 10 m/s and comes to rest at 8 sec.

✡ To Find ✡

⇝ What it's acceleration.

✡ Formula Used ✡

✴ v = u + at ✴

where,

v = final velocity

u = initial velocity

a = acceleration

t = time taken

▶ According to the question by using formula we get,

$⟹ 0 = 10 + (a) (8)$

$⟹ 0 = 10 + 8a$

$⟹ 10 + 8a = 0$

$⟹ 10 = - 8a$

$\implies \: a = \frac{ - 10}{8}$

$⟹ a = \dfrac{-5}{4} </p><p>$

⟹ a = - 1.25 m/s²

∴ Hence, the acceleration of the ball is - 1.25 m/s².