Question

A ball throw vertically afford with speed of 49m/s
1.maximum height gain by the ball
2.total time taken by the ball with earth surface..

Answer 1

The height it has attained is
$h = u {}^{2} \div 2g$
h=49×49/2×9.8
h=122.5m
The time taken is
$t = 2u \div g$
t=2×49/9.8
t=98/9.8
t=10sec..

Therefore,h=122.5m and t=10sec.
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