A ball thrown vertically upward returns to the thrower in 20 sec. Find the velocity with which it was thrown and the max. height attained by the ball
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Answer:
v = 100m/s & s = 500m
Explanation:
We have , Total time = 20s then time taken to reach the max height = 20/2 viz. = 10s
Now , using the formula : a = v - u / t
so , - 10 = 0 - u / 10 (a = -g= -10)
so, u = 100m/s
Total distance we can calculate by using formula
v^2 - u^2 = 2as : 0 - 10000 = -20s : s= 500m
Therefore , v= 100m/s & s = 500m
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