Question

A ball thrown vertically upward with a velocity of 49m/s.Calculate the MAXIMUM HEIGHT it can reach and also calculate its TIME OF FLIGHT

Answer 1

Explanation:

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Answer 2

Answer:

120m,  9.8s

Explanation:

Given Data: U0 = 49 m/s & $\alpha$ = 90 degrees.

Maximum Height = $u^2/2g$ = 49^2/2(10) =  120.05 m ~= 120m.

Time of Flight = $(2usin\alpha )/g$ = (2*49*1)/10 = 49/5 = 9.8 seconds