Question

A ball thrown vertically upwards after reaching maximum height h returns to the starting point after a time of 10 s. Its displacement after 5 s is (d) 20 h (c) 10h (b) 2h (a) h

Answer 1

Answer:

Explanation:

Distance after time 10 second

S=ut +1/2at^2

h=0*t+1/2*10*10^2

h=0+500

h=500m

Now at 5s

It is at 125 m

Displacement = 375 m