A block of mass 1 kg is attached to a spring of force constant nm . 4 25 −1 k = it is pulled 0.3 m from its equilibrium position and released from rest. this spring‐block apparatus is submerged in a viscous fluid medium which exerts a damping force of – 4 v (where v is the instantaneous velocity of the block). determine of the position x(t) of the block at time t
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mass of block = 1 kg
k = 4.25 N/m
f = - Kx
so by substituting this values -4 = -4.25 × x
x = 4 / 4.25
k = 4.25 N/m
f = - Kx
so by substituting this values -4 = -4.25 × x
x = 4 / 4.25
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