Question

A ball thrown vertically upwards with a speed of 19.6ms-1
from the top of a tower returns to the earth in 6 seconds.
Find the height of the tower (g=9.8ms-2)​

Answer 1

Answer:height of the tower is 58.8 m

Explanation:

Time taken= 6s

Going upward

V=0

U=19.6

a=-9.8

V=U+at

t=2s

So time taken to fall is 4s.

Going downward

S=a(t^2)/2

S=78.4m

While going upward distance covered = S=ut+a(t^2)/2

S=19.6

So height of the tower is

78.4-19.6=58.8