a balloon is ascending at rate of 5m/s at a height of 100 m above the ground when a packet is dropped from the balloon . after how much time does it reach the ground(take 10m/s as acceleration
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Answer:5.05 seconds
Explanation:hey here is your answer.
v=v0-gt=5–9.81t
s=s0+v0t-0.5gt^2
s=100+5t-0.5(9.81)t^2
when it reaches the ground s=0
9.81t^2–10t-200=0
t={-(-10)+/-[(-10)^2–4(9.81)(-200)]^0.5}/2(9.81)
={10+/-[100+7848]^0.5}/19.62
={10+/-[7948]^0.5}/19.62={10+/-89.15}/19.62=5.05 sec
only the positive root has meaning.
Therefore it will take about 5.05 seconds to hit the ground.
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