Question

A Batsman hit back a ball straight in the direction of the bowler without changing its initial speed of 12m/s. If the mass of the ball is 0.15kg determine the impluse imparted to the ball

Answer 1

Impulse = change in linear momentum .

initial momentum of ball= mu

=0.15 × 12 =1.8 kg.m/sec

final momentum of ball = -mu

= - 0.15 × 12 = -1.8 kgm/sec

now,

change in momentum of ball =final -initial

= -1.8 -1.8 = -3.6 kgm/sec

so,

change in momentum of bat = -change in momentum of ball

change in momentum of bat =3.6 kgm/s

now,

impulse imparted to ball =change in momentum of bat = 3.6 kgm/s

Answer 2

${\huge{\underline{\underline{\mathfrak{\red{♡ANSWER♡}}}}}}$.

✪. Change in momentum=${0.15×12-(-0.15×12)}$

✪. ${3.6Ns,}$

✪. $\red{\bold{\underline{\underline{Impulse}}}}$ = ${3.6Ns,}$

• In the direction from the batsman to the bowler .
• This is an example where the force on the ball by the batsman and the time of contact of the ball and the bat are difficult to know , but the impulse is readily calculated