what is hybridization of central atom of Xef2
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Z = Number of Valence electrons on central atom + (number of monovalent groups attached) - (charge with sign)
Now, divide Z by 2.
If z/2 =2 sp
z/2=3 sp2
z/2=4 sp3
z/2=5 sp3d
z/2=6 sp3d2
This works around 90% of the time.
So lets use this on XeF2
No. of valence electrons on central atom (Xe clearly) = 8
No. of monovalent groups (F) = 2
Charge = 0
Z = 8 + 2 - 0 = 10
Z/2 = 5
so hybridization = sp3d - this corresponds to a geometry of trigonal bi-pyramidal.
Hope this helps you ☺️☺️✌️✌️❤️❤️
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