Question

a batsman hits back a ball straight in the direction of the bowler without changing it's initial speed of 12m/s. if the mass of ball is 0.15 kg. determine the impulse imparted to the ball

Answer 1

Hey there!

Impulse = change in linear momentum .

Initial momentum of ball = mu

=0.15 × 12

= 1.8 kg.m/sec

Final momentum of ball = -mu

= - 0.15 × 12

= -1.8 kgm/sec

Now the,

Change in momentum of ball = final -initial

= -1.8 -1.8

= -3.6 kgm/sec

So,
change in momentum of bat = -change in momentum of ball

Change in momentum of bat = 3.6 kgm/s

Therefore,
Impulse imparted to ball =change in momentum of bat = 3.6 kgm/s

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Answer 2

${\huge{\underline{\underline{\mathfrak{\orange{♡ANSWER♡}}}}}}$.

✪. Change in momentum=${0.15×12-(-0.15×12)}$

✪. ${3.6Ns,}$

✪. $\blue{\bold{\underline{\underline{Impulse}}}}$ = ${3.6Ns,}$

• In the direction from the batsman to the bowler .
• This is an example where the force on the ball by the batsman and the time of contact of the ball and the bat are difficult to know , but the impulse is readily calculated