Physics, asked by harichandeela6133, 1 year ago

A battery having an emf of 12 volt and an internal resistance of 2 Ω is connected to another battery having an emf of 18 volt and an internal resistance of 2 Ω in such a way that they are opposing each other and the circuit is closed. Calculate the following :(1) current flowing in the circuit.(2) electrical power in the two batteries.(3) terminal voltage of the two batteries.(4) electric power consumed in the batteries.

Answers

Answered by Arslankincsem
2

If there is no emf of 12 volt, the current capacity has terminal voltage level and in case denotes R=V/I and battery stands at 12v.


If two resistors are connecting by resistance of 2ohm in parallel, the resistors having 10, 20, and 30 ohm connected in series.


A cell with an Emf are storing in internal resistance are taking terminal voltage of a battery.

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