Question

a battery lights a bulb describe the energy changes involved in the process calculate the amount of work needed to stop a car of 250 kilogram moving at a speed of 18 km per hour

Answer 1

$5 \div 18 \times 18 = 1m \: per \: second \\ now \: work = force \times displcement \\ \: \: = 250 \times 1 = 250att$