A battery of 9V is connected in series with resistors of 0.2 Ω , 0.3 Ω , 0.4 Ω , 0.5 Ω and 12Ω.
How much current will flow through 12Ω resistor ?
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8
the following line is : A will flow through 12 ohm resistor...
hope it helps....
hope it helps....
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Answered by
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V = IR
9 = I x 0.2 +0.3 + 0.4 + 0.5 + 12
9 = I x 13.4
9/ 13.4 = I
I = 0.67 Amperes
9 = I x 0.2 +0.3 + 0.4 + 0.5 + 12
9 = I x 13.4
9/ 13.4 = I
I = 0.67 Amperes
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