Question

A battery of e.m.f. 10 V and internal resistance 0.5 Ω is connected across a variable resistance R. The value of R for which the power delivered in it is maximum is given by(a) 0.5 Ω(b) 1.0 Ω(c) 2.0 Ω(d) 0.25 Ω

Answer 1

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D) 0.25 Ω

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Answer 2

Answer:

A) 0.5

Explanation:

Battery = 10V (Given)

Internal resistance = 0.5Ω (Given)

The output power of a cell is given by  P = I²R

Therefore, P = V²/(r+R)²R

Maximum power is delivered to the load only when the internal resistance of the source is equal to the load resistance denoted as (R). Thus,

Pmax - V²/4R = V²/4r (r = R)

For obtaining maximum power, the internal resistance must be equal to variable resistance so, the value of R will remain the same as 0.5Ω.