A beam AB of length 5m supported at A and B carries two point load w1 and w2 of 3KN and 5KN which are 1m Apart. It the reaction at B is 2KN more than that at A, find the distance between the support A and the load 3KN
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Given A beam AB of length 5m supported at A and B carries two point load w1 and w2 of 3KN and 5KN which are 1m Apart. It the reaction at B is 2KN more than that at A, find the distance between the support A and the load 3KN
- Now there is a beam AB
- So B = A + 2 (since it carries 2 KN more than A)
- Also A + B – 3 – 5 = 0
- So A + (A + 2) – 3 – 5 = 0
- So 2A – 6 = 0
- 2A = 6
- Or A = 6/2
- Or A = 3 KN
- So B = A + 2
- = 3 + 2
- B = 5 KN
- Now we have
- 3m + 5(m + 1) – B(5) = 0
- 3m + 5m + 5 – 5(5) = 0 (since B = 5)
- 8m + 5 – 25 = 0
- 8m – 20 = 0
- 8m = 20
- Or m = 20 / 8
- Or m = 2.5 m
Reference link will be
https://brainly.ph/question/5811135
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