Question

A block is made of two solids .a cone and a hemisphere .if the height and the base radius of the cone are 24 cm and 10 cm respectively and the diameter of the hemisphere is 10 cm find total surface area of the block. answer fast . it's urgent

Answer 1

HERE IS YOUR ANSWER:-

Total surface area of the solid

= CSA of cone plus CSA of hemisphere

= πrl+2πr2

= 22/7×5×25+2×22/7×5×5

= 392.897+157.14

= 550.03cm2

PLZ MARK MY ANSWER THE BRAINLIEST ONE.

Answer 2

Answer:

Step-by-step explanation:

In CONE

r=10cm                                      

h=24cm

L=?

By P.t Theorem                                  

$24^{2} + 10^{2} = L^{2}$

576+100=$L^{2}$

26=L

In HEMISPHERE

r=5cm

SURFACE AREA OF BLOCK = curved surface area of cone+ curved surface area of hemisphere+ area of bottom of cone- area of bottom of hemisphere.

=> $\pi *10 (26+10)+2\pi 5^{2}+\pi 10^{2} -\pi 5^{2}$

=> $\pi (360+50+100-25)$

=> $3.14 *485$

=>$1522.9cm^{2}$