Question

a block of mass 0.25 kg is placed on a light vertical spring of force constant 5000 N/m and pushed down ward so that the spring compressed to 0.1m. To what maximum height above the point of release it rise?

Answer 1

1/2 kx²= mgy

1/2x5000x(0.1)²=0.25x10x(y)

25=2.5y

Y=10m