Ques-1
Two identical metal spheres carry charges of + q and - 2q respectively. When the spheres are separated by
a large distance r, the force between them is F. Now the spheres are allowed to touch and then moved back
to the same separation. Find the new force of repulsion between them.
Answers
Answered by
8
Here is ur answer mate......
hope it helps you out
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Answer is F/8 but method is correct
Answered by
7
hey mate!!
Initial force,
F ={ k q (-2q)} / r^2.......(1)
now, whet are in contac5 wid each othe4 charge is equally distributed,
charge on each sphere =( q -2q) /2 = -q/2
New force,
F' =( k q/2*q/2 ) / r^2
F' = kq^2/4r^2...........(2)
from equations 1 and 2
F' = F/4
hope it helps!!
#Jaihind
Initial force,
F ={ k q (-2q)} / r^2.......(1)
now, whet are in contac5 wid each othe4 charge is equally distributed,
charge on each sphere =( q -2q) /2 = -q/2
New force,
F' =( k q/2*q/2 ) / r^2
F' = kq^2/4r^2...........(2)
from equations 1 and 2
F' = F/4
hope it helps!!
#Jaihind
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