Question

A block of mass 0.5 kg attached to a spring of force constant k has time period π / 2 seconds when amplitude is 0.16 m it force constant is​

Answer 1

Answer:

The amplitude is maximum when the frequency is 1.59Hz

This problem is based on the simple harmonic motion of a spring

The period of the motion T is given as

T =2π√m/k

Given data

Attached mass m= 1kg

Spring constant k =N/m

Substituting our data into the equation we have

T =2*3.142√1/100

T=6.284√0.01

T=6.284*0.1

T=0.63sec

But frequency f=1/T

f=1/0.63

f=1.59Hz

Explanation:

Hope this helps:)  ジョセフ