Question

A block of mass 1.0kg is hanged from an elastic wire of coss sectional area 1 sq.cm. find the value of the stree produced in the wire.

Answer 1

The value of the stress produced in the wire is $98000N/m^2$.

Explanation:

The stress in the wire is given as

$Stress=\frac{F}{A}$

Here, F is the applied force and A is area of cross-section.

The applied force is given as

F = mg

m = 1.0 kg (block hanged from an elastic wire) and g is the acceleration due to gravity.

So,

$F = 1 .0 kg \times9.8m/s^2$

F = 9.8 N.

Given $A = 1.0 cm^2=0.0001 m^2$

Substitute the values, we get

$Stress=\frac{9.8N}{0.0001m^2}$

$Stress=98000N/m^2$

Thus, the value of the stress produced in the wire is $98000N/m^2$.

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