A block of mass 200 grams is moving with a speed 4 metre per second at the highest point in a closed circular tube of radius 10 cm kept fixed in a vertical plane the cross section of the tubes is such that the block just fits in it the block just fits it. The block makes several
oscillation inside the tube and finally stop find the work done by the tube on the block during process
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ACCORDING TO WORK ENERGY THEOREM, WORK done by all the forces is equal to change in kinetic energy
SO W(gravity)+W(tube)=0.5m(V^2-U^2)
AS IT'S DIAMETER IS 0.2 METRE
SO WORK DONE BY GRAVITY IS MGH I.e. 0.2×10×0.2=0.4
Putting values, 0.4 +W(tube)=0.5×0.2×(0-16)
WORK DONE BY TUBE IS -2.0
NOTE G IS 10 HERE AND I HAVE CONVERTED ALL QUANTITIES TO METRE AND KG
PLEASE MARK IT BRAINLIEST ANSWER
SO W(gravity)+W(tube)=0.5m(V^2-U^2)
AS IT'S DIAMETER IS 0.2 METRE
SO WORK DONE BY GRAVITY IS MGH I.e. 0.2×10×0.2=0.4
Putting values, 0.4 +W(tube)=0.5×0.2×(0-16)
WORK DONE BY TUBE IS -2.0
NOTE G IS 10 HERE AND I HAVE CONVERTED ALL QUANTITIES TO METRE AND KG
PLEASE MARK IT BRAINLIEST ANSWER
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