Prove that Sin50-sin70+cos80=0
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sin50-sin70+cos80=2cos((70+50)/2)sin((50-70)/2)+cos80
=2cos60sin(-10)+cos80
=2×1/2×sin(-10)+cos80
=-sin10+cos80
=-cos(90-10)+cos80
=0=RHS
=2cos60sin(-10)+cos80
=2×1/2×sin(-10)+cos80
=-sin10+cos80
=-cos(90-10)+cos80
=0=RHS
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Step-by-step explanation:
this answer is correct. ....m
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