The total cost of 3 tables and 2 chair is rs 1850. If a table costs rs 75 more than a chair , find the cost of each
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Answered by
14
Let the cost of one chair and one table equal to x and y respectively.
Then,according to your question
3x + 2y = 1850
and the cost of a table is 75 more than a chair =>
y + 75 = x => y = x - 75
Coming back to the previous equation--
3x + 2y = 1850 (Here we substitute the value of y)
=>3x + 2(x - 75) = 1850
=>3x + 2x - 150 = 1850
=>5x = 2000
x = 2000/5 = 400
Now,we go back to our previous equation
y + 75 = x (Here substitute x)
y + 75 = 400
y = 325
So the cost of one table and one chair is 400 and 325 respectively.
Then,according to your question
3x + 2y = 1850
and the cost of a table is 75 more than a chair =>
y + 75 = x => y = x - 75
Coming back to the previous equation--
3x + 2y = 1850 (Here we substitute the value of y)
=>3x + 2(x - 75) = 1850
=>3x + 2x - 150 = 1850
=>5x = 2000
x = 2000/5 = 400
Now,we go back to our previous equation
y + 75 = x (Here substitute x)
y + 75 = 400
y = 325
So the cost of one table and one chair is 400 and 325 respectively.
Answered by
12
The total cost of 3 tables and 2 chair = ₹1850.
cost of a table = ₹75 + cost of chair
let x = cost of chair
Then cost of a table = 75+x
according to the problem
1850 = 3(75+x)+2x
= 225+3x+2x
= 225+5x
1850-225 = 5x
1625 = 5x
1625/5 = x
325 = x
cost of chair = 325
cost of table = 75+325
= 400
cost of a table = ₹75 + cost of chair
let x = cost of chair
Then cost of a table = 75+x
according to the problem
1850 = 3(75+x)+2x
= 225+3x+2x
= 225+5x
1850-225 = 5x
1625 = 5x
1625/5 = x
325 = x
cost of chair = 325
cost of table = 75+325
= 400
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