Question

a block of mass 24 kg floats on water the volume of wood is 0.032 m cube find the volume of block below the surface of water and density of wood given the density of water is 1000 kg per metre cube

Answer 1

Hey mate ^_^

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Answer:
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$Given:-$

Mass of the block of wood $= 24 kg$

Volume of wood $= 0.032 m^3$

Density of water $= 1000kg/m^3$

Now,

Density of wood is given by,

$\frac{m}{v} = \frac{24}{0.032}$

$\frac{m}{v} = 750 \: kg/m ^{3}$

Therefore,

The density of wood is $750kg/m^3$

By principle of floatation,

$Mass \:of\: wood = Mass\: of\: liquid \:displaced$

Therefore,

Mass of liquid displaced $= 24kg$

Volume of liquid displaced (v),

$\frac{m}{v} = \frac{24}{1000}$

$\frac{m}{v} = 0.24m ^{3}$

Now,

Since the volume of the wood is equal to the volume of water displaced, it is $0.024m^3$

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$Note:$
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=> The volume of the wood below the water surface is the volume of water displaced.

=> $Buoyant\: force = Weight\: of\: the \:displaced\: water.$

#Be Brainly❤️

Answer 2

Hey

here is answer

Given:-

Mass of the block of wood = 24 kg

Volume of wood = 0.032 m^3

Density of water = 1000kg/m^3

Now,

Density of wood is given by, 

$\begin{lgathered}\frac{m}{v} = \frac{24}{0.032} \\\end{lgathered}$

$\frac{m}{v} = 750 \: kg/m ^{3}$

Therefore, 

The density of wood is 750kg/m^3750kg/m3 

By principle of floatation,

$Mass \:of\: wood = Mass\: of\: liquid \:displaced$

Therefore, 

Mass of liquid displaced = 24kg=24kg 

Volume of liquid displaced (v), 

$\begin{lgathered}\frac{m}{v} = \frac{24}{1000} \\\end{lgathered}$

$\frac{m}{v} = 0.24m ^{3}$

Now, 

The volume of block below the surface of water will be, 

$\frac{0.024}{0.032} = 0.75m ^{3}$

hope it helps

Thanks