a block of mass 2kg rest on a rough inclined plane making an angle of 30 degree with hori zontal the coeficient of static friction between the block and the plane is .7 the friction force on block is
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mαѕѕ = 2kg
αmglє σf ínclínαtíσn between block and horizontal line is 30°
coefficient of friction = 0.7
Force that will slide the body is mgsin∅
2×9.8×0.5
= 9.8N
Limiting or static friction will be kmgcos∅
= 0.7×2×9.8×√3/2
=11.88N
as the limit infection is more than the force tends to slide the body the frictional force on body will be 9.8N and body will be at rest
αmglє σf ínclínαtíσn between block and horizontal line is 30°
coefficient of friction = 0.7
Force that will slide the body is mgsin∅
2×9.8×0.5
= 9.8N
Limiting or static friction will be kmgcos∅
= 0.7×2×9.8×√3/2
=11.88N
as the limit infection is more than the force tends to slide the body the frictional force on body will be 9.8N and body will be at rest
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